Let

be an algebraically closed field, complete for a
non-trivial ultrametric absolute value, and let
A be a
commutative normed

-algebra with identity. We call
multiplicative spectrum of
A the set

of continuous multiplicative
semi-norms on
A. We denote by

the set of
multiplicative semi-norms on the polynomial algebra
![$\Bbb K[X]$](img4.gif)
.
Both sets of semi-norms are endowed with the topology of pointwise
convergence. For any element
t of
A, we denote by

the evaluation homomorphism from
![$\Bbb K[X]$](img4.gif)
to
A. We call the
Gelfand transform of
t the mapping

from

to

defined by

.
We then call
spectrum of
t the
subset of

:

.
This set

satisfies a
formula analogous to the spectral radius formula in the complex
case. We denote by

the set of the

in

whose kernel is a maximal
ideal of
A. We then put

,
and

.
We give a large condition on
A, for these sets to satisfy the same kind of spectral radius
formulæ. This is done by using holomorphic functional calculus
with algebras of functions defined on compact subsets of

.
In particular, we use a metric topology on

thinner than the topology of pointwise convergence, but we show
that both topologies have exactly the same connected sets, and
also prove that connectedness is equivalent to arcwise
connectedness.